Updated at 21:13,24-10-2016

Lukashenka said to have won almost 80 percent

20-12-2010, 13:18
Lukashenka said to have won almost 80 percent

Lidziya Yarmoshyna, head of the central election commission, announced at about 4:30 a.m. on Monday that according to preliminary data, Alyaksandr Lukashenka had won 79.67 percent of the vote, or 5,122,866 votes.

As for his opponents, Ms. Yarmoshyna said that Andrey Sannikaw had garnered 2.56 percent (164,000 votes), Yaraslaw Ramanchuk 1.97 percent (126,986 votes), Ryhor Kastusyow 1.97 percent (126,645 votes), Uladzimir Nyaklyayew 1.77 percent (113,747 votes), Ales Mikhalevich 1.2 percent (65,598 votes), Vital Rymashewski 1.1 percent (70,433 votes), Viktar Tsyareshchanka 1.08 percent (69,653 votes), Mikalay Statkevich 1.04 percent (67,000 votes), and Dzmitry Uss 0.48 percent (31,000 votes).

According to Ms. Yarmoshyna, 6.47 percent of the voters voted against all candidates.

Mr. Lukashenka was said to have won 83 percent of the vote in the previous, 2006 presidential election compared with 6.1 percent for his main rival, opposition politician Alyaksandr Milinkevich.

In the 2001 election, Mr. Lukashenko was said to have gained 75.65 percent, while Uladzimir Hancharyk, a trade union leader who ran as the common candidate of opposition forces, came second with 15.65 percent.